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Solve for rr.\newline8=r3+68 = \frac{r}{3} + 6\newliner=r = _____

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Q. Solve for rr.\newline8=r3+68 = \frac{r}{3} + 6\newliner=r = _____
  1. Equation Isolation: We have the equation:\newline8=r3+68 = \frac{r}{3} + 6\newlineTo isolate r3\frac{r}{3}, we need to subtract 66 from both sides of the equation.\newline8−6=r3+6−68 - 6 = \frac{r}{3} + 6 - 6\newline2=r32 = \frac{r}{3}
  2. Finding r Value: Now that we have r/3r/3, we need to find the value of rr. To do this, we multiply both sides of the equation by 33. 2×3=r3×32 \times 3 = \frac{r}{3} \times 3 6=r6 = r

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