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Solve for rr.\newline3r+1=73r + 1 = 7\newliner=r = _____

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Full solution

Q. Solve for rr.\newline3r+1=73r + 1 = 7\newliner=r = _____
  1. Subtract 11 to isolate r: Subtract 11 from both sides to isolate the term with rr.3r+1−1=7−13r + 1 - 1 = 7 - 13r=63r = 6
  2. Divide both sides for r: Divide both sides by 33 to solve for rr.\newline3r3=63\frac{3r}{3} = \frac{6}{3}\newliner=2r = 2

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