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Solve for rr.\newline3(r+4)=33(r + -4) = -3\newliner=r = _____

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Q. Solve for rr.\newline3(r+4)=33(r + -4) = -3\newliner=r = _____
  1. Distribute and Simplify: Simplify the equation by distributing the 33 into (r+4)(r + -4).3(r+4)=3r+3(4)3(r + -4) = 3r + 3(-4)=3r12= 3r - 12
  2. Add 1212 to Both Sides: Add 1212 to both sides to isolate the term with rr.3r12+12=3+123r - 12 + 12 = -3 + 123r=93r = 9
  3. Divide to Solve for r: Divide both sides by 33 to solve for rr.3r3=93\frac{3r}{3} = \frac{9}{3}r=3r = 3

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