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Solve for rr.−10−5r=−6r−1 r=…\begin{array}{l} -10-5r=-6r-1 \ r=\dots \end{array}

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Domain and range of absolute value functions: equationsright chevron icon

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Q. Solve for rr.−10−5r=−6r−1 r=…\begin{array}{l} -10-5r=-6r-1 \ r=\dots \end{array}
  1. Given System of Equations: We are given the system of equations:\newline−10−5r=−6r−1-10 - 5r = -6r - 1\newlineLet's isolate the variable rr on one side of the equation by adding 6r6r to both sides.\newline−10−5r+6r=−6r−1+6r-10 - 5r + 6r = -6r - 1 + 6r\newlineThis simplifies to:\newline−10+r=−1-10 + r = -1
  2. Isolate Variable rr: Now, let's isolate rr completely by adding 1010 to both sides of the equation.\newline−10+r+10=−1+10-10 + r + 10 = -1 + 10\newlineThis simplifies to:\newliner=9r = 9

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