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Solve for qq.\newline2q=−10+4q\sqrt{2q} = \sqrt{-10 + 4q}\newlineq=q = _____

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Full solution

Q. Solve for qq.\newline2q=−10+4q\sqrt{2q} = \sqrt{-10 + 4q}\newlineq=q = _____
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(2q)2=(–10+4q)2(\sqrt{2q})^2 = (\sqrt{\text{–}10 + 4q})^2\newline2q=–10+4q2q = \text{–}10 + 4q
  2. Subtract q terms: Subtract 4q4q from both sides to get all q terms on one side.\newline2q−4q=−10+4q−4q2q - 4q = -10 + 4q - 4q\newline−2q=−10-2q = -10
  3. Divide by −2-2: Divide both sides by −2-2 to solve for qq.\newline−2q/−2=−10/−2-2q / -2 = -10 / -2\newlineq=5q = 5

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