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Solve for $q$ . $\newline$ $4(q + 6) + 3 \leq 11$

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Solve linear inequalities

Full solution

Q. Solve for

q

.

\newline

4(q + 6) + 3 \leq 11

Distribute and Simplify: First, distribute the $4$ into the parentheses. $4(q + 6) + 3 \leq 11$ $4q + 24 + 3 \leq 11$
Combine Like Terms: Next, combine like terms on the left side. $4q + 27 \leq 11$
Isolate q: Now, subtract $27$ from both sides to isolate the term with $q$ . $\newline$ $4q + 27 - 27 \leq 11 - 27$ $\newline$ $4q \leq -16$
Solve for q: Finally, divide both sides by $4$ to solve for $q$ . $\frac{4q}{4} \leq \frac{-16}{4}$ $q \leq -4$

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