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Solve for pp.\newline4=p+834 = p + \frac{8}{3}\newlinep=p = _____

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Full solution

Q. Solve for pp.\newline4=p+834 = p + \frac{8}{3}\newlinep=p = _____
  1. Isolate variable pp: Isolate the variable pp by subtracting 83\frac{8}{3} from both sides of the equation.\newline4=p+834 = p + \frac{8}{3}\newline4−83=p+83−834 - \frac{8}{3} = p + \frac{8}{3} - \frac{8}{3}\newline4−83=p4 - \frac{8}{3} = p
  2. Convert whole number to fraction: Convert the whole number 44 to a fraction with the same denominator as 83\frac{8}{3} to combine the terms.\newline44 can be written as 123\frac{12}{3} because 4×33=1234 \times \frac{3}{3} = \frac{12}{3}.\newline123−83=p\frac{12}{3} - \frac{8}{3} = p
  3. Subtract fractions: Subtract the fractions.\newline(123)−(83)=p(\frac{12}{3}) - (\frac{8}{3}) = p\newline(12−83)=p(\frac{12 - 8}{3}) = p\newline43=p\frac{4}{3} = p

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