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Solve for pp.\newline0<p+16<130 < p + 16 < 13\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A)p<16p < -16 or p3p \geq -3\newline(B)16<p3-16 < p \leq -3\newline(C)16<p<3-16 < p < -3\newline(D)p<16p < -16 or p>3p > -3

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Q. Solve for pp.\newline0<p+16<130 < p + 16 < 13\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A)p<16p < -16 or p3p \geq -3\newline(B)16<p3-16 < p \leq -3\newline(C)16<p<3-16 < p < -3\newline(D)p<16p < -16 or p>3p > -3
  1. Isolate pp in compound inequality: First, we will isolate pp in the compound inequality by subtracting 1616 from all three parts of the inequality.\newline0<p+16<130 < p + 16 < 13\newline016<p+1616<13160 - 16 < p + 16 - 16 < 13 - 16\newline16<p<3-16 < p < -3
  2. Identify range for pp: Now that we have isolated pp, we can see that pp must be greater than 16-16 and less than 3-3. This matches one of the given choices.

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