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Solve for k k .\newline2k=8k+10 \sqrt{2k} = \sqrt{8k + 10} \newlinek= k = _____

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Q. Solve for k k .\newline2k=8k+10 \sqrt{2k} = \sqrt{8k + 10} \newlinek= k = _____
  1. Square Roots Elimination: First, we need to eliminate the square roots by squaring both sides of the equation. \newline2k=8k+10\sqrt{2k} = \sqrt{8k + 10}\newline(2k)2=(8k+10)2(\sqrt{2k})^2 = (\sqrt{8k + 10})^2\newline2k=8k+102k = 8k + 10
  2. Variable Isolation: Next, we need to isolate the variable kk on one side of the equation.2k=8k+102k = 8k + 102k8k=8k+108k2k - 8k = 8k + 10 - 8k6k=10-6k = 10
  3. Dividing to Solve for k: Now, we divide both sides by 6-6 to solve for kk.6k=10-6k = 10k=106k = \frac{10}{-6}k=53k = -\frac{5}{3}

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