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Solve for kk.\newline2(k+7)=202(k + 7) = 20\newlinek=k = _____

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Q. Solve for kk.\newline2(k+7)=202(k + 7) = 20\newlinek=k = _____
  1. Distribute 22: Distribute the 22 across the parentheses.\newlineWe need to apply the distributive property to remove the parentheses. This means we multiply 22 by both kk and 77.\newlineCalculation: 2×k+2×7=2k+142 \times k + 2 \times 7 = 2k + 14
  2. Set up equation: Set up the equation after distribution.\newlineThe equation after distributing the 22 is 2k+14=202k + 14 = 20.
  3. Subtract 1414: Subtract 1414 from both sides of the equation to isolate the term with kk. We want to get kk on one side of the equation by itself, so we need to remove the 1414 from the left side. Calculation: 2k+1414=20142k + 14 - 14 = 20 - 14, which simplifies to 2k=62k = 6.
  4. Divide by 22: Divide both sides of the equation by 22 to solve for kk. To find the value of kk, we divide both sides of the equation by 22. Calculation: 2k2=62\frac{2k}{2} = \frac{6}{2}, which simplifies to k=3k = 3.