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Solve for kk.\newline10≤k+11<2010 \leq k + 11 < 20\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A) −1≤k<31-1 \leq k < 31\newline(B) −1≤k<9-1 \leq k < 9\newline(C) 21≤k<3121 \leq k < 31\newline(D) 21≤k<921 \leq k < 9

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Q. Solve for kk.\newline10≤k+11<2010 \leq k + 11 < 20\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A) −1≤k<31-1 \leq k < 31\newline(B) −1≤k<9-1 \leq k < 9\newline(C) 21≤k<3121 \leq k < 31\newline(D) 21≤k<921 \leq k < 9
  1. Analyze Compound Inequality: Analyze the given compound inequality.\newlineThe inequality 10≤k+11<2010 \leq k + 11 < 20 involves two inequalities combined: one is 10≤k+1110 \leq k + 11 and the other is k+11<20k + 11 < 20. We need to isolate kk in both inequalities.
  2. Subtract to Isolate kk: Subtract 1111 from all parts of the compound inequality to isolate kk.10−11≤k+11−11<20−1110 - 11 \leq k + 11 - 11 < 20 - 11−1≤k<9-1 \leq k < 9
  3. Check Solution: Check the solution against the provided choices.\newlineThe solution we found is −1≤k<9-1 \leq k < 9, which matches choice (B)(B).

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