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Solve for jj.\newline −2j= −6−4j\sqrt{\,-2j} = \sqrt{\,-6 - 4j}\newlinej= ____j = \,\_\_\_\_

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Full solution

Q. Solve for jj.\newline −2j= −6−4j\sqrt{\,-2j} = \sqrt{\,-6 - 4j}\newlinej= ____j = \,\_\_\_\_
  1. Square both sides: Square both sides of the equation to eliminate the square roots.\newline(−2j)2=(−6−4j)2(\sqrt{-2j})^2 = (\sqrt{-6 - 4j})^2\newline−2j=−6−4j-2j = -6 - 4j
  2. Add jj terms: Add 4j4j to both sides of the equation to get all the jj terms on one side.\newline−2j+4j=−6−4j+4j-2j + 4j = -6 - 4j + 4j\newline2j=−62j = -6
  3. Divide by 22: Divide both sides by 22 to solve for jj.2j2=−62\frac{2j}{2} = \frac{-6}{2}j=−3j = -3

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