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Solve for jj.\newline4j2=3(13j+2)4j - 2 = 3\left(\frac{1}{3}j + 2\right)\newlinej=j = __

Full solution

Q. Solve for jj.\newline4j2=3(13j+2)4j - 2 = 3\left(\frac{1}{3}j + 2\right)\newlinej=j = __
  1. Distribute terms in parentheses: Distribute 33 to the terms inside the parentheses on the right side of the equation.\newline4j2=3×(13j+2)4j - 2 = 3 \times \left(\frac{1}{3}j + 2\right)\newline=3×13j+3×2= 3 \times \frac{1}{3}j + 3 \times 2\newline=j+6= j + 6
  2. Subtract to isolate variable: Subtract jj from both sides to start isolating the variable.\newline4jj2=j+6j4j - j - 2 = j + 6 - j\newline3j2=63j - 2 = 6
  3. Add to further isolate term: Add 22 to both sides to further isolate the term with jj. \newline3j2+2=6+23j - 2 + 2 = 6 + 2\newline3j=83j = 8
  4. Divide to solve for j: Divide both sides by 33 to solve for jj. \newline3j3=83\frac{3j}{3} = \frac{8}{3}\newlinej=83j = \frac{8}{3}