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Solve for jj. \newline3j+12≤−9(j+20)3j + 12 \leq -9(j + 20)\newlineWrite your answer with jj first, followed by an inequality symbol.\newline______

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Q. Solve for jj. \newline3j+12≤−9(j+20)3j + 12 \leq -9(j + 20)\newlineWrite your answer with jj first, followed by an inequality symbol.\newline______
  1. Add 9j9j to both sides: Now, add 9j9j to both sides to get all the jj terms on one side.\newline3j+9j+12≤−9j+9j−1803j + 9j + 12 \leq -9j + 9j - 180\newline12j+12≤−18012j + 12 \leq -180
  2. Subtract 1212 from both sides: Next, subtract 1212 from both sides to isolate the term with jj.12j+12−12≤−180−1212j + 12 - 12 \leq -180 - 1212j≤−19212j \leq -192
  3. Divide both sides by 1212: Finally, divide both sides by 1212 to solve for jj.12j12≤−19212\frac{12j}{12} \leq \frac{-192}{12}j≤−16j \leq -16

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