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Solve for $h$ . $\newline$ $17 \geq h + 6 \geq 16$ $\newline$ Write your answer as a compound inequality with integers. $\newline$ Choices: $\newline$ (A) $11 > h \geq 10$ $\newline$ (B) $h > 11$ or $h \leq 10$ $\newline$ (C) $11 \geq h \geq 10$ $\newline$ (D) $h \geq 11$ or $h \leq 10$

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Solve compound inequalities

Full solution

Q. Solve for

h

.

\newline

17 \geq h + 6 \geq 16

\newline

Write your answer as a compound inequality with integers.

\newline

Choices:

\newline

(A)

11 > h \geq 10

\newline

(B)

h > 11

or

h \leq 10

\newline

(C)

11 \geq h \geq 10

\newline

(D)

h \geq 11

or

h \leq 10

Analyze Inequality: Analyze the compound inequality $17 \geq h + 6 \geq 16$ . Which operation should we use to isolate $h$ ? In $h + 6$ , $6$ is being added to $h$ . Subtraction should be used to isolate $h$ .
Subtract $6$ : Subtract $6$ from all parts of the inequality $17 \geq h + 6 \geq 16$ . $\newline$ $17 - 6 \geq h + 6 - 6 \geq 16 - 6$ $\newline$ $11 \geq h \geq 10$
Write Compound Inequality: Write the answer as a compound inequality with integers. $\newline$ The inequality $11 \geq h \geq 10$ matches one of the given choices.

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