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Let’s check out your problem:
Solve for
h
h
h
.
\newline
−
15
h
−
17
+
14
=
15
−
13
h
-15h - 17 + 14 = 15 - 13h
−
15
h
−
17
+
14
=
15
−
13
h
\newline
h
=
h =
h
=
__
View step-by-step help
Home
Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
Solve for
h
h
h
.
\newline
−
15
h
−
17
+
14
=
15
−
13
h
-15h - 17 + 14 = 15 - 13h
−
15
h
−
17
+
14
=
15
−
13
h
\newline
h
=
h =
h
=
__
Simplify equation:
First, simplify both sides of the equation by combining like terms.
\newline
−
15
h
−
17
+
14
=
15
−
13
h
-15h - 17 + 14 = 15 - 13h
−
15
h
−
17
+
14
=
15
−
13
h
\newline
−
15
h
−
3
=
15
−
13
h
-15h - 3 = 15 - 13h
−
15
h
−
3
=
15
−
13
h
Combine h terms:
Next, add
13
h
13h
13
h
to both sides to get all the h terms on one side.
\newline
−
15
h
+
13
h
−
3
=
15
−
13
h
+
13
h
-15h + 13h - 3 = 15 - 13h + 13h
−
15
h
+
13
h
−
3
=
15
−
13
h
+
13
h
\newline
−
2
h
−
3
=
15
-2h - 3 = 15
−
2
h
−
3
=
15
Isolate h term:
Then, add
3
3
3
to both sides to isolate the term with
h
h
h
.
\newline
−
2
h
−
3
+
3
=
15
+
3
-2h - 3 + 3 = 15 + 3
−
2
h
−
3
+
3
=
15
+
3
\newline
−
2
h
=
18
-2h = 18
−
2
h
=
18
Solve for h:
Finally, divide both sides by
−
2
-2
−
2
to solve for
h
h
h
.
−
2
h
−
2
=
18
−
2
\frac{-2h}{-2} = \frac{18}{-2}
−
2
−
2
h
=
−
2
18
h
=
−
9
h = -9
h
=
−
9
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(B) Exactly one solution
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6
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Choose
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answer:
\newline
(A) No solutions
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(B) Exactly one solution
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How many solutions does the following equation have?
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\newline
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\newline
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(B) Exactly one solution
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\newline
Choose
1
1
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answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
9
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=
16
z
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6
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\newline
Choose
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\newline
(A) No solutions
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(B) Exactly one solution
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(C) Infinitely many solutions
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