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Solve for
h.

{:[15.3+1h=1.3-1h],[h=]:}

Solve for $h$ . $\newline$ $\begin{array}{l} 15.3+1 h=1.3-1 h \\ h= \end{array}$

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Sine and cosine of complementary angles

Full solution

Q. Solve for

h

.

\newline

\begin{array}{l} 15.3+1 h=1.3-1 h \\ h= \end{array}

Addition of h terms: We are given a system of equations with only one equation shown, which is: $\newline$ $15.3 + 1h = 1.3 - 1h$ $\newline$ To solve for $h$ , we need to isolate $h$ on one side of the equation. Let's start by adding $1h$ to both sides to move all the $h$ terms to one side.
Simplify equation: After adding $1h$ to both sides, the equation becomes: $\newline$ $15.3 + 1h + 1h = 1.3 - 1h + 1h$ $\newline$ This simplifies to: $\newline$ $15.3 + 2h = 1.3$
Subtract constant term: Next, we need to get $h$ by itself. To do this, we will subtract $15.3$ from both sides of the equation to move the constant term to the other side.
Isolate $h$ : After subtracting $15.3$ from both sides, the equation becomes: $\newline$ $15.3 + 2h - 15.3 = 1.3 - 15.3$ $\newline$ This simplifies to: $\newline$ $2h = -14$
Divide by $2$ : Now, we divide both sides by $2$ to solve for $h$ .
Final solution: After dividing by $2$ , the equation becomes: $\newline$ $\frac{2h}{2} = \frac{-14}{2}$ $\newline$ This simplifies to: $\newline$ $h = -7$

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