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Solve for gg.\newline2g−1=12g - 1 = 1\newlineg=g = _____\_\_\_\_\_

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Full solution

Q. Solve for gg.\newline2g−1=12g - 1 = 1\newlineg=g = _____\_\_\_\_\_
  1. Add 11 to isolate gg: Add 11 to both sides to isolate the term with gg.2g−1+1=1+12g - 1 + 1 = 1 + 12g=22g = 2
  2. Divide by 22 to solve: Divide both sides by 22 to solve for gg.2g2=22\frac{2g}{2} = \frac{2}{2}g=1g = 1

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