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Solve for ff.\newline12f+10>1012 \geq f + 10 > 10\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A)2>f02 > f \geq 0\newline(B)2f02 \geq f \geq 0\newline(C)2f>02 \geq f > 0\newline(D)2>f>02 > f > 0

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Q. Solve for ff.\newline12f+10>1012 \geq f + 10 > 10\newlineWrite your answer as a compound inequality with integers.\newlineChoices:\newline(A)2>f02 > f \geq 0\newline(B)2f02 \geq f \geq 0\newline(C)2f>02 \geq f > 0\newline(D)2>f>02 > f > 0
  1. Analyze Compound Inequality: Analyze the given compound inequality.\newlineThe inequality is 12f+10>1012 \geq f + 10 > 10. We need to isolate ff by subtracting 1010 from all parts of the inequality.
  2. Subtract 1010: Subtract 1010 from all parts of the inequality.\newline1210f+1010>101012 - 10 \geq f + 10 - 10 > 10 - 10\newline2f>02 \geq f > 0
  3. Write Final Answer: Write the final answer as a compound inequality with integers.\newlineThe final answer is 2f>02 \geq f > 0, which matches choice (C)(C).

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