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Solve for $f$ . $10 + 8f < 2$

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Solve two-step inequalities

Full solution

Q. Solve for

f

.

10 + 8f < 2

Isolate variable f: Start by isolating the variable f on one side of the inequality. Subtract $10$ from both sides of the inequality to get $8f$ by itself. $\newline$ $10 + 8f - 10 < 2 - 10$ $\newline$ $8f < -8$
Subtract $10$ : Divide both sides of the inequality by $8$ to solve for $f$ . $\frac{8f}{8} < \frac{-8}{8}$ $f < -1$
Divide by $8$ : Check the solution by substituting $f$ with a number less than $-1$ into the original inequality to see if it holds true. $\newline$ Let's choose $f = -2$ as a test value. $\newline$ $10 + 8(-2) < 2$ $\newline$ $10 - 16 < 2$ $\newline$ $-6 < 2$ $\newline$ This is true, so $f < -1$ is a valid solution to the inequality.

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