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Solve for dd.\newlined12=1d - 12 = 1\newlined=d = _____

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Q. Solve for dd.\newlined12=1d - 12 = 1\newlined=d = _____
  1. Isolate dd: d12=1d - 12 = 1 \newlineTo solve for dd, we need to isolate dd on one side of the equation.\newlineWe can do this by adding 1212 to both sides of the equation to cancel out the 12-12 on the left side.\newlined12+12=1+12d - 12 + 12 = 1 + 12
  2. Add 1212: d=13d = 13\newlineAfter adding 1212 to both sides, we find that dd equals 1313.\newlineThis is the value of dd that satisfies the equation.