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Solve for dd.\newline12(d+4)=d1\frac{1}{2}(d + 4) = d - 1\newlined = ____

Full solution

Q. Solve for dd.\newline12(d+4)=d1\frac{1}{2}(d + 4) = d - 1\newlined = ____
  1. Distribute terms: Distribute 12\frac{1}{2} to the terms inside the parentheses.\newline12(d+4)=12×d+12×4=12d+2\frac{1}{2}(d + 4) = \frac{1}{2} \times d + \frac{1}{2} \times 4 = \frac{1}{2}d + 2
  2. Subtract to isolate dd: Subtract 12d\frac{1}{2}d from both sides to start isolating dd.
    12d+212d=d112d\frac{1}{2}d + 2 - \frac{1}{2}d = d - 1 - \frac{1}{2}d
    2=12d12 = \frac{1}{2}d - 1
  3. Add to isolate 12d\frac{1}{2}d: Add 11 to both sides to further isolate 12d\frac{1}{2}d. \newline2+1=12d1+12 + 1 = \frac{1}{2}d - 1 + 1\newline3=12d3 = \frac{1}{2}d
  4. Multiply to solve for dd: Multiply both sides by 22 to solve for dd.2×3=12d×22 \times 3 = \frac{1}{2}d \times 26=d6 = d