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Solve for cc.\newline8=2c+(−2)8 = 2c + (-2)\newlinec=c = _____

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Full solution

Q. Solve for cc.\newline8=2c+(−2)8 = 2c + (-2)\newlinec=c = _____
  1. Add 22 to isolate c: Add 22 to both sides to isolate the term with cc. \newline8+2=2c+(−2)+28 + 2 = 2c + (-2) + 2\newline10=2c10 = 2c
  2. Divide to solve for c: Divide both sides by 22 to solve for cc.102=2c2\frac{10}{2} = \frac{2c}{2}c=5c = 5

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