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Solve for cc.\newline2c3=32c - 3 = 3\newlinec=c = _____\_\_\_\_\_

Full solution

Q. Solve for cc.\newline2c3=32c - 3 = 3\newlinec=c = _____\_\_\_\_\_
  1. Add 33 to isolate c: Add 33 to both sides to isolate the term with cc.2c3+3=3+32c - 3 + 3 = 3 + 32c=62c = 6
  2. Divide both sides by 22: Divide both sides by 22 to solve for cc.2c2=62\frac{2c}{2} = \frac{6}{2}c=3c = 3