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Solve for cc.\newline2(c+10)=22(c + -10) = -2\newlinec=c = _____

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Q. Solve for cc.\newline2(c+10)=22(c + -10) = -2\newlinec=c = _____
  1. Distribute and Multiply: Distribute the 22 across the parentheses.\newlineMultiply 22 by each term inside the parentheses.\newline2(c+10)=2c+2(10)=2c202(c + -10) = 2c + 2(-10) = 2c - 20
  2. Set Equation Equal: Set the equation equal to 2–2.\newline2c20=22c – 20 = –2
  3. Add to Isolate: Add 2020 to both sides to isolate the term with the variable cc. \newline2c20+20=2+202c - 20 + 20 = -2 + 20\newline2c=182c = 18
  4. Divide to Solve: Divide both sides by 22 to solve for cc.2c2=182\frac{2c}{2} = \frac{18}{2}c=9c = 9