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Solve for cc.\newline19c−9c−4c+3=1519c - 9c - 4c + 3 = 15\newlinec = ____

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Full solution

Q. Solve for cc.\newline19c−9c−4c+3=1519c - 9c - 4c + 3 = 15\newlinec = ____
  1. Combine like terms: Combine like terms on the left side of the equation.\newline19c−9c−4c+3=1519c - 9c - 4c + 3 = 15\newline(19−9−4)c+3=15(19 - 9 - 4)c + 3 = 15\newline6c+3=156c + 3 = 15
  2. Subtract to isolate: Subtract 33 from both sides to isolate the term with the variable cc.\newline6c+3−3=15−36c + 3 - 3 = 15 - 3\newline6c=126c = 12
  3. Divide to solve: Divide both sides by 66 to solve for cc.6c6=126\frac{6c}{6} = \frac{12}{6}c=2c = 2

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