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Solve for bb.\newlineb3+6=7\frac{b}{3} + 6 = 7\newlineb=b = _____

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Full solution

Q. Solve for bb.\newlineb3+6=7\frac{b}{3} + 6 = 7\newlineb=b = _____
  1. Subtract 66 from both sides: Isolate the variable term b3\frac{b}{3} by subtracting 66 from both sides of the equation.b3+6−6=7−6\frac{b}{3} + 6 - 6 = 7 - 6
  2. Simplify the equation: Simplify both sides of the equation. b3=1\frac{b}{3} = 1
  3. Multiply by 33: Multiply both sides of the equation by 33 to solve for bb.3×(b3)=1×33 \times \left(\frac{b}{3}\right) = 1 \times 3
  4. Find the value of bb: Simplify both sides of the equation to find the value of bb.b=3b = 3

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