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Solve for bb.\newlineb+3=12(b4)b + 3 = \frac{1}{2}(b - 4)\newlineb = ____

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Q. Solve for bb.\newlineb+3=12(b4)b + 3 = \frac{1}{2}(b - 4)\newlineb = ____
  1. Distribute 12\frac{1}{2} to terms: Distribute 12\frac{1}{2} to the terms inside the parentheses in the equation b+3=12(b4)b + 3 = \frac{1}{2}(b - 4).\newlineCalculation: \newline12(b4)=12×b12×4\frac{1}{2}(b - 4) = \frac{1}{2} \times b - \frac{1}{2} \times 4\newline=12b2= \frac{1}{2} b - 2\newlineRewritten equation: b+3=12b2b + 3 = \frac{1}{2} b - 2
  2. Get all bb terms: Get all bb terms on one side by subtracting 12b\frac{1}{2} b from both sides.\newlineCalculation:\newlineb+312b=12b212bb + 3 - \frac{1}{2} b = \frac{1}{2} b - 2 - \frac{1}{2} b\newline12b+3=2\frac{1}{2} b + 3 = -2