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Solve for bb.\newline−4b−16=−2b+18-4b - 16 = -2b + 18\newlineb=b = __

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Full solution

Q. Solve for bb.\newline−4b−16=−2b+18-4b - 16 = -2b + 18\newlineb=b = __
  1. Add 1616 to both sides: Now, we add 1616 to both sides to isolate the b term.\newline−2b−16+16=18+16-2b - 16 + 16 = 18 + 16\newline−2b=34-2b = 34
  2. Divide by −2-2: Finally, we divide both sides by −2-2 to solve for bb.−2b−2=34−2\frac{-2b}{-2} = \frac{34}{-2}b=−17b = -17

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