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Solve for bb.\newline2(b+5)+8=8-2(b + 5) + 8 = 8\newlineb=b = _____\_\_\_\_\_

Full solution

Q. Solve for bb.\newline2(b+5)+8=8-2(b + 5) + 8 = 8\newlineb=b = _____\_\_\_\_\_
  1. Distribute 2-2: Simplify the equation by distributing 2-2 into (b+5)(b + 5).
    2(b+5)+8=8-2(b + 5) + 8 = 8
    2b10+8=8-2b - 10 + 8 = 8
  2. Combine like terms: Combine like terms on the left side.\newline2b2=8-2b - 2 = 8
  3. Add 22 to isolate: Add 22 to both sides to isolate the term with bb.2b2+2=8+2-2b - 2 + 2 = 8 + 22b=10-2b = 10
  4. Divide by 2-2: Divide both sides by 2-2 to solve for bb.2b2=102\frac{-2b}{-2} = \frac{10}{-2}b=5b = -5