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Solve for bb.\newline2(b10)=142(b - 10) = 14\newlineb=b = _____

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Q. Solve for bb.\newline2(b10)=142(b - 10) = 14\newlineb=b = _____
  1. Distribute 22: Distribute the 22 across the parentheses.\newlineWe need to apply the distributive property to remove the parentheses. This means we multiply 22 by both bb and 10-10.\newline2(b10)=2b2102(b − 10) = 2\cdot b − 2\cdot 10\newline2b20=142b − 20 = 14
  2. Add 2020: Add 2020 to both sides of the equation to isolate the term with the variable bb. We want to get bb by itself on one side of the equation, so we need to undo the subtraction of 2020. 2b20+20=14+202b - 20 + 20 = 14 + 20 2b=342b = 34
  3. Divide by 22: Divide both sides of the equation by 22 to solve for bb.\newlineNow we divide both sides by 22 to find the value of bb.\newline2b2=342\frac{2b}{2} = \frac{34}{2}\newlineb=17b = 17