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Solve for bb.\newline1=b2−11 = \frac{b}{2} - 1\newlineb=b = _____\_\_\_\_\_

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Full solution

Q. Solve for bb.\newline1=b2−11 = \frac{b}{2} - 1\newlineb=b = _____\_\_\_\_\_
  1. Add 11 to isolate b: Add 11 to both sides of the equation to isolate the term containing bb.1+1=b2−1+11 + 1 = \frac{b}{2} - 1 + 12=b22 = \frac{b}{2}
  2. Multiply by 22 to solve: Multiply both sides by 22 to solve for bb.2×2=b2×22 \times 2 = \frac{b}{2} \times 24=b4 = b

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