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Let’s check out your problem:
Solve for all values of
x
x
x
:
\newline
4
x
(
2
x
−
3
)
+
9
(
2
x
−
3
)
=
0
4 x(2 x-3)+9(2 x-3)=0
4
x
(
2
x
−
3
)
+
9
(
2
x
−
3
)
=
0
\newline
Answer:
x
=
x=
x
=
View step-by-step help
Home
Math Problems
Algebra 1
Solve multi-step linear equations
Full solution
Q.
Solve for all values of
x
x
x
:
\newline
4
x
(
2
x
−
3
)
+
9
(
2
x
−
3
)
=
0
4 x(2 x-3)+9(2 x-3)=0
4
x
(
2
x
−
3
)
+
9
(
2
x
−
3
)
=
0
\newline
Answer:
x
=
x=
x
=
Factor out common term:
Factor out the common term
(
2
x
−
3
)
(2x-3)
(
2
x
−
3
)
.
4
x
(
2
x
−
3
)
+
9
(
2
x
−
3
)
=
(
2
x
−
3
)
(
4
x
+
9
)
=
0
4x(2x-3) + 9(2x-3) = (2x-3)(4x+9) = 0
4
x
(
2
x
−
3
)
+
9
(
2
x
−
3
)
=
(
2
x
−
3
)
(
4
x
+
9
)
=
0
Set equal to zero:
Set each factor equal to zero to find the values of
x
x
x
. First, set the first factor equal to zero:
2
x
−
3
=
0
2x - 3 = 0
2
x
−
3
=
0
Solve for x:
Solve for x from the first factor.
\newline
2
x
−
3
=
0
2x - 3 = 0
2
x
−
3
=
0
\newline
Add
3
3
3
to both sides:
\newline
2
x
=
3
2x = 3
2
x
=
3
\newline
Divide by
2
2
2
:
\newline
x
=
3
2
x = \frac{3}{2}
x
=
2
3
Set second factor:
Set the second factor equal to zero:
\newline
4
x
+
9
=
0
4x + 9 = 0
4
x
+
9
=
0
Solve for x:
Solve for x from the second factor.
\newline
4
x
+
9
=
0
4x + 9 = 0
4
x
+
9
=
0
\newline
Subtract
9
9
9
from both sides:
\newline
4
x
=
−
9
4x = -9
4
x
=
−
9
\newline
Divide by
4
4
4
:
\newline
x
=
−
9
4
x = -\frac{9}{4}
x
=
−
4
9
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Question
Solve for x.
\newline
(
3
4
)
x
=
12
(\frac{3}{4})x= 12
(
4
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)
x
=
12
\newline
x
=
x =
x
=
______
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Solve for x.
\newline
−
5
9
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−
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\newline
x
=
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______
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Question
How many solutions does the following equation have?
\newline
5
x
+
8
−
7
x
=
−
4
x
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5
x
+
8
−
7
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=
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4
x
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\newline
Choose
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1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
−
2
z
+
10
+
7
z
=
16
z
+
7
-2z+10+7z=16z+7
−
2
z
+
10
+
7
z
=
16
z
+
7
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
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Question
How many solutions does the following equation have?
\newline
7
(
y
−
8
)
=
7
y
+
42
7(y-8)=7y+42
7
(
y
−
8
)
=
7
y
+
42
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
9
(
x
+
6
)
=
−
9
x
+
108
-9(x+6)=-9x+108
−
9
(
x
+
6
)
=
−
9
x
+
108
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
6
(
x
+
7
)
=
−
4
x
−
2
-6(x+7)=-4x-2
−
6
(
x
+
7
)
=
−
4
x
−
2
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
−
4
x
−
7
+
10
x
=
−
7
+
6
x
-4x-7+10x=-7+6x
−
4
x
−
7
+
10
x
=
−
7
+
6
x
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
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Question
How many solutions does the following equation have?
\newline
−
17
(
y
−
2
)
=
−
17
y
+
64
-17(y-2)=-17y+64
−
17
(
y
−
2
)
=
−
17
y
+
64
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
Question
How many solutions does the following equation have?
\newline
9
z
−
6
+
7
z
=
16
z
−
6
9z-6+7z=16z-6
9
z
−
6
+
7
z
=
16
z
−
6
\newline
Choose
1
1
1
answer:
\newline
(A) No solutions
\newline
(B) Exactly one solution
\newline
(C) Infinitely many solutions
Get tutor help
Posted 1 year ago
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