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Solve by the method of your choice.
Twenty-two people purchase raflle tickets. Three winning tickets are selected at random. If first prize is 
$1000, second price is 
$500, and third prize is 
$100, in how many different ways can the prizes be awarded?
There are different ways in which the prizes can be awarded.
(Simplify your answer.)

Solve by the method of your choice.\newlineTwenty-two people purchase raflle tickets. Three winning tickets are selected at random. If first prize is $1000 \$ 1000 , second price is $500 \$ 500 , and third prize is $100 \$ 100 , in how many different ways can the prizes be awarded?\newlineThere are different ways in which the prizes can be awarded.\newline(Simplify your answer.)

Full solution

Q. Solve by the method of your choice.\newlineTwenty-two people purchase raflle tickets. Three winning tickets are selected at random. If first prize is $1000 \$ 1000 , second price is $500 \$ 500 , and third prize is $100 \$ 100 , in how many different ways can the prizes be awarded?\newlineThere are different ways in which the prizes can be awarded.\newline(Simplify your answer.)
  1. Determine Number of Ways: We need to determine the number of ways to award three distinct prizes to three people out of 2222. This is a permutation problem because the order in which the prizes are awarded matters (first, second, and third are distinct).
  2. Select First Prize Winner: First, we select a winner for the first prize. There are 2222 possible people who could win this prize.
  3. Select Second Prize Winner: After awarding the first prize, we have 2121 remaining people who could win the second prize.
  4. Select Third Prize Winner: Finally, after awarding the second prize, we have 2020 remaining people who could win the third prize.
  5. Calculate Total Number of Ways: To find the total number of ways the three prizes can be awarded, we multiply the number of choices for each prize together: 2222 choices for the first prize, 2121 choices for the second prize, and 2020 choices for the third prize.
  6. Perform Multiplication: The calculation is 22×21×2022 \times 21 \times 20.
  7. Final Result: Performing the multiplication gives us 22×21×20=924022 \times 21 \times 20 = 9240.
  8. Final Result: Performing the multiplication gives us 22×21×20=924022 \times 21 \times 20 = 9240.Therefore, there are 92409240 different ways the three prizes can be awarded.

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