Solve by the method of your choice.Twenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is $1000, second prize is $500, and third prize is $100, in how many different ways can the prizes be awarded?There are □ different ways in which the prizes can be awarded.(Simplify yous answer.)
Q. Solve by the method of your choice.Twenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is $1000, second prize is $500, and third prize is $100, in how many different ways can the prizes be awarded?There are □ different ways in which the prizes can be awarded.(Simplify yous answer.)
Understand the problem: Understand the problem.We need to find the number of different ways to award three distinct prizes to three winners out of 22 ticket holders.
Determine the method: Determine the method to use.Since the order in which the prizes are awarded matters (first, second, and third are distinct), we will use permutations to solve this problem.
Calculate permutations: Calculate the number of permutations.The number of ways to choose the first prize winner is 22 (since there are 22 ticket holders). After the first prize is awarded, there are 21 ticket holders left for the second prize, and then 20 ticket holders left for the third prize.The number of permutations is therefore 22×21×20.
Perform the calculation: Perform the calculation.Now we calculate the number of permutations: 22×21×20=9240.
Verify the calculation: Verify the calculation.To verify, we can quickly re-calculate using a calculator or by hand to ensure that 22×21×20 indeed equals 9240.