Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve by the method of your choice.
Twenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is 
$1000, second prize is 
$500, and third prize is 
$100, in how many different ways can the prizes be awarded?
There are 
◻ different ways in which the prizes can be awarded.
(Simplify yous answer.)

Solve by the method of your choice.\newlineTwenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is $1000 \$ 1000 , second prize is $500 \$ 500 , and third prize is $100 \$ 100 , in how many different ways can the prizes be awarded?\newlineThere are \square different ways in which the prizes can be awarded.\newline(Simplify yous answer.)

Full solution

Q. Solve by the method of your choice.\newlineTwenty-two people purchase raffle tickets. Three winning tickets are selected at random. If first prize is $1000 \$ 1000 , second prize is $500 \$ 500 , and third prize is $100 \$ 100 , in how many different ways can the prizes be awarded?\newlineThere are \square different ways in which the prizes can be awarded.\newline(Simplify yous answer.)
  1. Understand the problem: Understand the problem.\newlineWe need to find the number of different ways to award three distinct prizes to three winners out of 2222 ticket holders.
  2. Determine the method: Determine the method to use.\newlineSince the order in which the prizes are awarded matters (first, second, and third are distinct), we will use permutations to solve this problem.
  3. Calculate permutations: Calculate the number of permutations.\newlineThe number of ways to choose the first prize winner is 2222 (since there are 2222 ticket holders). After the first prize is awarded, there are 2121 ticket holders left for the second prize, and then 2020 ticket holders left for the third prize.\newlineThe number of permutations is therefore 22×21×2022 \times 21 \times 20.
  4. Perform the calculation: Perform the calculation.\newlineNow we calculate the number of permutations: 22×21×20=924022 \times 21 \times 20 = 9240.
  5. Verify the calculation: Verify the calculation.\newlineTo verify, we can quickly re-calculate using a calculator or by hand to ensure that 22×21×2022 \times 21 \times 20 indeed equals 92409240.

More problems from Counting principle