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Solve.\newline4x+2y=14-4x + 2y = -14\newlinex=5x = 5\newline(_____, _____)

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Q. Solve.\newline4x+2y=14-4x + 2y = -14\newlinex=5x = 5\newline(_____, _____)
  1. Substitute x=5x = 5: Substitute x=5x = 5 into the equation 4x+2y=14–4x + 2y = –14.\newline4(5)+2y=14–4(5) + 2y = –14\newline20+2y=14–20 + 2y = –14
  2. Isolate variable y: Isolate the variable y by adding 2020 to both sides of the equation.\newline20+2y+20=14+20-20 + 2y + 20 = -14 + 20\newline2y=62y = 6
  3. Divide by 22: Divide both sides of the equation by 22 to solve for y.\newline2y2=62\frac{2y}{2} = \frac{6}{2}\newliney=3y = 3
  4. Find values of xx and yy: We have found the values of xx and yy:x=5x = 5y=3y = 3The solution in the form of an ordered pair is (5,3)(5, 3).

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