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Solve.\newline3x3y=18-3x - 3y = -18\newlinex=2x = 2\newline(_____, _____)

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Q. Solve.\newline3x3y=18-3x - 3y = -18\newlinex=2x = 2\newline(_____, _____)
  1. Given Equations: Given the system of equations:\newline3x3y=18-3x - 3y = -18\newlinex=2x = 2\newlineWe will substitute x=2x = 2 into the first equation to find the value of yy.
  2. Substitute x=2x = 2: Substitute x=2x = 2 into the first equation.\newline3(2)3y=18–3(2) − 3y = –18\newline63y=18–6 − 3y = –18
  3. Isolate variable term: Isolate the variable term to solve for yy.3y=18+6\,-3y = -18 + 63y=12\,-3y = -12
  4. Divide by 3-3: Divide both sides by 3–3 to find the value of yy.y=123y = \frac{–12}{–3}y=4y = 4
  5. Final Solution: We have found the values of xx and yy.\newlinex=2x = 2\newliney=4y = 4\newlineThe solution in the form of an ordered pair is (2,4)(2, 4).

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