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Solve.\newline3x+2y=18-3x + 2y = -18\newlinex=10x = 10\newline(_____, _____)

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Q. Solve.\newline3x+2y=18-3x + 2y = -18\newlinex=10x = 10\newline(_____, _____)
  1. Substitute x=10x = 10: Substitute x=10x = 10 into the first equation 3x+2y=18–3x + 2y = –18.
    3(10)+2y=18-3(10) + 2y = -18
    30+2y=18-30 + 2y = -18
  2. Isolate variable yy: Isolate the variable yy by adding 3030 to both sides of the equation.\newline30+2y+30=18+30-30 + 2y + 30 = -18 + 30\newline2y=122y = 12
  3. Divide to solve yy: Divide both sides of the equation by 22 to solve for yy.2y2=122\frac{2y}{2} = \frac{12}{2}y=6y = 6
  4. Find values of xx and yy: We have found the values of xx and yy:x=10x = 10y=6y = 6The solution in the form of an ordered pair is (10,6)(10, 6).

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