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Solve.

3(z+6)=33
Answer: 
z=

Solve.\newline3(z+6)=33 3(z+6)=33 \newlineAnswer: z= z=

Full solution

Q. Solve.\newline3(z+6)=33 3(z+6)=33 \newlineAnswer: z= z=
  1. Distribute Terms: Distribute the 33 to both terms inside the parentheses.\newlineWe need to apply the distributive property, which states that a(b+c)=ab+aca(b + c) = ab + ac. In this case, we distribute 33 to both zz and 66.\newline3(z)+3(6)=333(z) + 3(6) = 33\newline3z+18=333z + 18 = 33
  2. Subtract 1818: Subtract 1818 from both sides of the equation to isolate the term with the variable zz. To solve for zz, we need to get zz on one side of the equation by itself. We do this by subtracting 1818 from both sides. 3z+1818=33183z + 18 - 18 = 33 - 18 3z=153z = 15
  3. Divide by 33: Divide both sides of the equation by 33 to solve for zz. Now that we have 3z=153z = 15, we divide both sides by 33 to find the value of zz. 3z3=153\frac{3z}{3} = \frac{15}{3} z=5z = 5