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3(z+2)=9

Solve.\newline3(z+2)=9 3(z+2)=9

Full solution

Q. Solve.\newline3(z+2)=9 3(z+2)=9
  1. Distribute 33: First, we need to distribute the 33 across the terms inside the parentheses.3(z+2)=93(z+2) = 93z+32=93\cdot z + 3\cdot 2 = 93z+6=93z + 6 = 9
  2. Isolate variable term: Next, we isolate the variable term 3z3z by subtracting 66 from both sides of the equation.3z+66=963z + 6 - 6 = 9 - 63z=33z = 3
  3. Solve for z: Finally, we solve for z by dividing both sides of the equation by 33. \newline3z3=33\frac{3z}{3} = \frac{3}{3}\newlinez=1z = 1

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