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Solve 
2+log_(3)(7x)=4

Solve 2+log3(7x)=4 2+\log _{3}(7 x)=4

Full solution

Q. Solve 2+log3(7x)=4 2+\log _{3}(7 x)=4
  1. Isolate logarithmic term: Step 11: Isolate the logarithmic term.\newline2+log3(7x)=42 + \log_3(7x) = 4\newlinelog3(7x)=42\log_3(7x) = 4 - 2\newlinelog3(7x)=2\log_3(7x) = 2
  2. Convert to exponential form: Step 22: Convert the logarithmic equation to its exponential form.\newline3log3(7x)=323^{\log_3(7x)} = 3^2\newline7x=97x = 9
  3. Solve for x: Step 33: Solve for x.\newline7x=97x = 9\newlinex=97x = \frac{9}{7}

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