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Solution
qquad 9. What is the total weight of the pieces of driftwood Soo collects most often?
(A)
11(3)/(4) pounds
(B)
22(1)/(4) pounds
(c)
33(3)/(8) pounds
(D)
33(3)/(4) pounds
66 Lesson 27 Make Line Plots and Interpret Data

Solution $\qquad$ $9$ . What is the total weight of the pieces of driftwood Soo collects most often? $\newline$ (A) $11 \frac{3}{4}$ pounds $\newline$ (B) $22 \frac{1}{4}$ pounds $\newline$ (c) $33 \frac{3}{8}$ pounds $\newline$ (D) $33 \frac{3}{4}$ pounds $\newline$ $66$ Lesson $27$ Make Line Plots and Interpret Data

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Full solution

Q. Solution

\qquad

9

. What is the total weight of the pieces of driftwood Soo collects most often?

\newline

(A)

11 \frac{3}{4}

pounds

\newline

(B)

22 \frac{1}{4}

pounds

\newline

(c)

33 \frac{3}{8}

pounds

\newline

(D)

33 \frac{3}{4}

pounds

\newline

66

Lesson

27

Make Line Plots and Interpret Data

Find Data on Weights: First, we need to find the data about the weights of the driftwood pieces Soo collects most often from the given information.
Sum Up Weights: Assuming the data is provided in the problem (which is not included in the prompt), we sum up the weights of the driftwood pieces that Soo collects most often.
Calculate Total Weight: Let's say Soo collects $3$ pieces of driftwood weighing $3\left(\frac{3}{4}\right)$ pounds each, and $2$ pieces weighing $4\left(\frac{1}{2}\right)$ pounds each.
Calculate $3(\frac{3}{4})$ Pound Pieces: Calculate the total weight of the $3(\frac{3}{4})$ pound pieces: $3 \times 3(\frac{3}{4}) = 3 \times (\frac{15}{4}) = \frac{45}{4}$ pounds.
Calculate $4(\frac{1}{2})$ Pound Pieces: Calculate the total weight of the $4(\frac{1}{2})$ pound pieces: $2 \times 4(\frac{1}{2}) = 2 \times (\frac{9}{2}) = \frac{18}{2} = 9$ pounds.
Add Total Weights: Add the total weights of both types of pieces: $(\frac{45}{4}) + 9 = (\frac{45}{4}) + (\frac{36}{4}) = \frac{81}{4}$ pounds.
Convert to Mixed Number: Convert $\frac{81}{4}$ pounds to a mixed number: $\frac{81}{4} = 20\left(\frac{1}{4}\right)$ pounds.

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