Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Simplify. Write your answer using whole numbers and variables. $\newline$ $\frac{2q^2 - 7q}{31q}$

View step-by-step help

View step-by-step help

Powers of a power: variable bases

Full solution

Q. Simplify. Write your answer using whole numbers and variables.

\newline

\frac{2q^2 - 7q}{31q}

Identify Terms and Factors: Identify the terms in the expression and look for common factors. $\newline$ The expression is $2q^2 - \frac{7q}{31q}$ . We can see that there is a common factor of $q$ in the numerator and the denominator of the second term.
Simplify Second Term: Simplify the second term by canceling out the common factor of $q$ . The $q$ in the numerator and the $q$ in the denominator of the second term cancel each other out, so we have: $2q^2 - \frac{7}{31}$
Combine Like Terms: Since there are no like terms to combine, the expression is already simplified. $\newline$ The first term, $2q^2$ , does not have any common factors with the second term, $\frac{7}{31}$ , and they are not like terms, so we cannot simplify any further.
Write Final Expression: Write the final simplified expression. $\newline$ The final simplified expression is: $\newline$ $2q^2 - \frac{7}{31}$

More problems from Powers of a power: variable bases

Question

Write the expression using an exponent.

\newline

2 \times 2

\newline

Posted 3 months ago

Question

Evaluate the expression.

4 - 4^2

Posted 3 months ago

Question

x^2 = 4

Posted 2 months ago

Question

x^2 = 9

Posted 4 months ago

Question

\newline

x^2 = 0

\newline

Write your answer in simplified, rationalized form.

\newline

x =

x =

Posted 4 months ago

Question

x

\newline

8 = 2^x

\newline

x =

Posted 4 months ago

Question

x

\newline

6 = 7^x

\newline

x =

Posted 4 months ago

Question

Select the equivalent expression.

\newline

((8^{-5})/(2^{-2}))^{-4}=?

\newline

1

\newline

\newline

(8^{20})/(2^{8})

\newline

\newline

(2^{6})/(8^{9})

\newline

\newline

(1)/(8\cdot 2^{2})

Posted 17 days ago

Question

Select the equivalent expression.

\newline

\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?

\newline

1

\newline

\frac{b^{21}}{4^{15}}

\newline

\frac{4^{15}}{b^{21}}

\newline

b^{-21}\cdot 4^{-15}

Posted 2 months ago

Question

Select the equivalent expression.

\newline

(3^{3}\cdot6^{6})^{-3}=

\newline

1

\newline

\frac{1}{3^{9}\cdot6^{18}}

\newline

\frac{6^{18}}{3^{9}}

\newline

\frac{3^{9}}{6^{18}}

Posted 2 months ago