Simplify the expression to a + bi form: (2-7i)(5-7i) Answer:

Distribute Terms: Distribute each term in the first complex number by each term in the second complex number. (2-7i)(5-7i) = 2*5 + 2*(-7i) + (-7i)*5 + (-7i)*(-7i)Perform Multiplication: Perform the multiplication for each term. 2*5 = 10 2*(-7i) = -14i (-7i)*5 = -35i (-7i)*(-7i) = 49i^2 (Remember that i^2 = -1)Combine Terms: Substitute i^2 with -1 and combine like terms. 10 + (-14i) + (-35i) + 49(-1) 10 - 14i - 35i - 49Substitute and Combine: Combine the real numbers and the imaginary numbers. (10 - 49) + (-14i - 35i) -39 - 49i

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Simplify the expression to a + bi form:

(2-7i)(5-7i)
Answer:

Simplify the expression to a + bi form: $\newline$ $(2-7 i)(5-7 i)$ $\newline$ Answer:

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Algebra 2

Simplify variable expressions using properties

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Q. Simplify the expression to a + bi form:

\newline

(2-7 i)(5-7 i)

\newline

Answer:

Distribute Terms: Distribute each term in the first complex number by each term in the second complex number. $\newline$ $(2-7i)(5-7i) = 2\cdot 5 + 2\cdot (-7i) + (-7i)\cdot 5 + (-7i)\cdot (-7i)$
Perform Multiplication: Perform the multiplication for each term. $\newline$ $2\times5 = 10$ $\newline$ $2\times(-7i) = -14i$ $\newline$ $(-7i)\times5 = -35i$ $\newline$ $(-7i)\times(-7i) = 49i^2$ (Remember that $i^2 = -1$ )
Combine Terms: Substitute $i^2$ with $-1$ and combine like terms. $\newline$ $10 + (-14i) + (-35i) + 49(-1)$ $\newline$ $10 - 14i - 35i - 49$
Substitute and Combine: Combine the real numbers and the imaginary numbers. $\newline$ $(10 - 49) + (-14i - 35i)$ $\newline$ $-39 - 49i$