Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Simplify the expression: \newline3+5+7q3 + 5 + 7q

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Grade 8right chevron icon
Add and subtract linear expressionsright chevron icon

Full solution

Q. Simplify the expression: \newline3+5+7q3 + 5 + 7q
  1. Identify Like Terms: Identify like terms in the expression 3+5+7q3 + 5 + 7q. In this expression, 33 and 55 are like terms because they are both constants without variables. The term 7q7q is not like any other term because it contains a variable.
  2. Combine Like Terms: Combine the like terms 33 and 55.3+5=83 + 5 = 8 Now we have the simplified expression 8+7q8 + 7q.
  3. Write Final Expression: Write the final simplified expression.\newlineSince there are no more like terms to combine, the expression is fully simplified as 8+7q8 + 7q.

More problems from Add and subtract linear expressions

Question
z=6.2+37iRe⁡(z)=Im⁡(z)= \begin{array}{l}z=6.2+37 i \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
z=4.1i+85Re⁡(z)=Im⁡(z)= \begin{array}{l}z=4.1 i+85 \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
z=6−3iRe⁡(z)=Im⁡(z)= \begin{array}{l}z=6-3 i \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
z=14i+12.1Re⁡(z)=Im⁡(z)= \begin{array}{l}z=14 i+12.1 \\ \operatorname{Re}(z)= \\ \operatorname{Im}(z)=\end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
log⁡1612= \log _{16} \frac{1}{2}=
Get tutor helpright-arrow

Posted 4 months ago

Question
What is the midline equation of\newliney=−4sin⁡(2x−7)+3?y=□ \begin{array}{l} y=-4 \sin (2 x-7)+3 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
What is the midline equation of\newliney=−5cos⁡(2πx+1)−10?y=□ \begin{array}{l} y=-5 \cos (2 \pi x+1)-10 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
What is the midline equation of\newliney=sin⁡(3x+5)?y=□ \begin{array}{l} y=\sin (3 x+5) ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
What is the midline equation of the function\newlineg(x)=2cos⁡(7x+5)+1?y=□ \begin{array}{l} g(x)=2 \cos (7 x+5)+1 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 4 months ago

Question
What is the midline equation of\newliney=10cos⁡(6x−1)−4?y=□ \begin{array}{l} y=10 \cos (6 x-1)-4 ? \\ y=\square \end{array}
Get tutor helpright-arrow

Posted 4 months ago

View all (13)