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Simplify. Rationalize the denominator. \newline93+2\frac{9}{3 + \sqrt{2}}

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Q. Simplify. Rationalize the denominator. \newline93+2\frac{9}{3 + \sqrt{2}}
  1. Identify Conjugate of Denominator: Identify the conjugate of the denominator.\newlineThe conjugate of a number of the form a+ba + \sqrt{b} is aba - \sqrt{b}. Therefore, the conjugate of 3+23 + \sqrt{2} is 323 - \sqrt{2}.
  2. Multiply by Conjugate: Multiply the numerator and the denominator by the conjugate of the denominator.\newlineTo rationalize the denominator, we multiply the numerator and the denominator by the conjugate of the denominator.\newline(9×(32))/((3+2)×(32))(9 \times (3 - \sqrt{2})) / ((3 + \sqrt{2}) \times (3 - \sqrt{2}))
  3. Simplify Numerator: Simplify the numerator.\newlineMultiply 99 by each term in the conjugate.\newline9×39×29 \times 3 - 9 \times \sqrt{2}\newline= 279×227 - 9 \times \sqrt{2}
  4. Simplify Denominator: Simplify the denominator.\newlineUse the difference of squares formula, which states that (a+b)(ab)=a2b2(a + b)(a - b) = a^2 - b^2.\newline(3+2)(32)=32(2)2(3 + \sqrt{2}) * (3 - \sqrt{2}) = 3^2 - (\sqrt{2})^2\newline=92= 9 - 2\newline=7= 7
  5. Write Final Expression: Write the simplified expression.\newlineNow that we have simplified both the numerator and the denominator, we can write the final expression.\newline(279×2)/7(27 - 9 \times \sqrt{2}) / 7\newlineThis fraction is already in simplest form.

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