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Simplify. Rationalize the denominator. \newline62+3\frac{6}{2 + \sqrt{3}}

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Q. Simplify. Rationalize the denominator. \newline62+3\frac{6}{2 + \sqrt{3}}
  1. Identify conjugate of denominator: Identify the conjugate of the denominator 2+32 + \sqrt{3}. The conjugate of a+ba + \sqrt{b} is aba - \sqrt{b}. Therefore, the conjugate of 2+32 + \sqrt{3} is 232 - \sqrt{3}.
  2. Multiply by conjugate: Multiply the numerator and the denominator by the conjugate of the denominator.\newlineTo rationalize the denominator, we multiply the fraction by 11 in the form of the conjugate over itself: 2323\frac{2 - \sqrt{3}}{2 - \sqrt{3}}.\newlineThis gives us 6×(23)(2+3)×(23)\frac{6 \times (2 - \sqrt{3})}{(2 + \sqrt{3}) \times (2 - \sqrt{3})}.
  3. Simplify numerator by distributing: Simplify the numerator by distributing the 66. \newline6×(23)6 \times (2 - \sqrt{3}) equals 126×312 - 6 \times \sqrt{3}.
  4. Simplify denominator using formula: Simplify the denominator by using the difference of squares formula.\newline(2+3)×(23)(2 + \sqrt{3}) \times (2 - \sqrt{3}) equals 22(3)22^2 - (\sqrt{3})^2.\newlineThis simplifies to 434 - 3, which equals 11.
  5. Write simplified fraction: Write the simplified fraction.\newlineSince the denominator is now 11, the fraction simplifies to just the numerator: 126×312 - 6 \times \sqrt{3}.

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