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Simplify. Rationalize the denominator.\newline325\frac{3}{-2 - \sqrt{5}}

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Q. Simplify. Rationalize the denominator.\newline325\frac{3}{-2 - \sqrt{5}}
  1. Identify Conjugate of Denominator: Identify the conjugate of the denominator.\newlineThe conjugate of aba - \sqrt{b} is a+ba + \sqrt{b}. Therefore, the conjugate of 25-2 - \sqrt{5} is 2+5-2 + \sqrt{5}.
  2. Multiply by Conjugate: Multiply the numerator and the denominator by the conjugate of the denominator.\newlineTo rationalize the denominator, we multiply both the numerator and the denominator by the conjugate of the denominator.\newline3×(2+5)(25)×(2+5)\frac{3 \times (-2 + \sqrt{5})}{(-2 - \sqrt{5}) \times (-2 + \sqrt{5})}
  3. Apply Difference of Squares: Apply the difference of squares formula to the denominator.\newlineThe difference of squares formula is (ab)(a+b)=a2b2(a - b)(a + b) = a^2 - b^2. Applying this to the denominator we get:\newline(2)2(5)2=45=1(-2)^2 - (\sqrt{5})^2 = 4 - 5 = -1.
  4. Distribute Numerator: Distribute the numerator.\newlineMultiply 33 by each term in the conjugate.\newline3×(2)+3×5=6+35.3 \times (-2) + 3 \times \sqrt{5} = -6 + 3\sqrt{5}.
  5. Combine and Simplify: Combine the results and simplify.\newlineSince the denominator simplifies to 1-1, we divide the entire numerator by 1-1 to get the final simplified form.\newline(6+35)/1=635(-6 + 3\sqrt{5}) / -1 = 6 - 3\sqrt{5}.

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