Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Simplify. Express your answer using a single exponent. $\newline$ $(7s^9)^2$

View step-by-step help

View step-by-step help

Powers of a power: variable bases

Full solution

Q. Simplify. Express your answer using a single exponent.

\newline

(7s^9)^2

Apply Power Rule: Apply the power of a power rule to $(7s^9)^2$ . The power of a power rule states that when raising a power to another power, you multiply the exponents. In this case, we have an exponent of $2$ being applied to both $7$ and $s^9$ . $(7s^9)^2 = 7^2 \times (s^9)^2$
Calculate $7^2$ : Calculate $7^2$ . $\newline$ $7^2$ is $7$ multiplied by itself. $\newline$ $7^2 = 7 \times 7 = 49$
Calculate $(s^9)^2$ : Calculate $(s^9)^2$ . Using the power of a power rule, we multiply the exponents $9$ and $2$ . $(s^9)^2 = s^{(9 \times 2)} = s^{18}$
Combine Results: Combine the results from Step $2$ and Step $3$ . $\newline$ We have $49$ for $7^2$ and $s^{18}$ for $(s^9)^2$ , so we combine them to get the final simplified expression. $\newline$ $(7s^9)^2 = 49s^{18}$

More problems from Powers of a power: variable bases

Question

Write the expression using an exponent.

\newline

2 \times 2

\newline

Posted 3 months ago

Question

Evaluate the expression.

4 - 4^2

Posted 3 months ago

Question

x^2 = 4

Posted 2 months ago

Question

x^2 = 9

Posted 4 months ago

Question

\newline

x^2 = 0

\newline

Write your answer in simplified, rationalized form.

\newline

x =

x =

Posted 4 months ago

Question

x

\newline

8 = 2^x

\newline

x =

Posted 4 months ago

Question

x

\newline

6 = 7^x

\newline

x =

Posted 4 months ago

Question

Select the equivalent expression.

\newline

((8^{-5})/(2^{-2}))^{-4}=?

\newline

1

\newline

\newline

(8^{20})/(2^{8})

\newline

\newline

(2^{6})/(8^{9})

\newline

\newline

(1)/(8\cdot 2^{2})

Posted 17 days ago

Question

Select the equivalent expression.

\newline

\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?

\newline

1

\newline

\frac{b^{21}}{4^{15}}

\newline

\frac{4^{15}}{b^{21}}

\newline

b^{-21}\cdot 4^{-15}

Posted 2 months ago

Question

Select the equivalent expression.

\newline

(3^{3}\cdot6^{6})^{-3}=

\newline

1

\newline

\frac{1}{3^{9}\cdot6^{18}}

\newline

\frac{6^{18}}{3^{9}}

\newline

\frac{3^{9}}{6^{18}}

Posted 2 months ago