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Simplify. Assume qq is greater than or equal to zero.\newline8q2\sqrt{8q^2}

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Q. Simplify. Assume qq is greater than or equal to zero.\newline8q2\sqrt{8q^2}
  1. Factorize 8q28q^2: Factor 8q28q^2 into its prime factors and pair the squares.\newlineThe prime factorization of 88 is 2×2×22 \times 2 \times 2, and q2q^2 is already a square. So, we have:\newline8q2=2×2×2×q×q\sqrt{8q^2} = \sqrt{2 \times 2 \times 2 \times q \times q}
  2. Group Factors into Pairs: Group the factors into pairs of squares.\newlineWe can group the factors as follows:\newline2×2×2×q×q=(2×2)×(q×q)×2\sqrt{2 \times 2 \times 2 \times q \times q} = \sqrt{(2 \times 2) \times (q \times q) \times 2}\newline= 4×q2×2\sqrt{4 \times q^2 \times 2}
  3. Simplify Square Roots: Simplify the square root of the squares.\newlineSince the square root of a square is just the base, we can simplify:\newline4q22=4q22\sqrt{4 \cdot q^2 \cdot 2} = \sqrt{4} \cdot \sqrt{q^2} \cdot \sqrt{2}\newline=2q2= 2 \cdot q \cdot \sqrt{2}

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